Definition 3.4.1. A function f : S → ℝ is uniformly continuous if for every ε > 0
there exists δ > 0 such that whenever x, c ∈ S with |x - c| < δ, then
|f x - f c| < ε.
Equations
Instances For
The book definition of uniform continuity on a subset of ℝ is equivalent to the standard
UniformContinuous predicate for functions on the subtype.
Example 3.4.2. The square function ℝ → ℝ is not uniformly continuous on the entire real
line.
Theorem 3.4.4. If f : ℝ → ℝ is continuous on the closed interval [a, b], then f is
uniformly continuous on [a, b].
Lemma 3.4.5. If f : S → ℝ is uniformly continuous and (x_n) is a Cauchy sequence in S,
then (f x_n) is also Cauchy.
Proposition 3.4.6. Suppose a < b. A function f : (a, b) → ℝ is uniformly continuous if
and only if the limits L_a = lim_{x → a} f x, L_b = lim_{x → b} f x exist and an extension to
the closed interval sending a to L_a, b to L_b, and agreeing with f on (a, b) is
continuous.
Definition 3.4.7. A function f : S → ℝ is Lipschitz continuous if there exists
K ∈ ℝ such that |f x - f y| ≤ K * |x - y| for all x, y ∈ S.
Instances For
The book definition of Lipschitz continuity on a subset of ℝ coincides with the
existence of some ℝ≥0 Lipschitz constant for the subtype.
Proposition 3.4.8. A Lipschitz continuous function is uniformly continuous.
Example 3.4.9. The sine function ℝ → ℝ is Lipschitz continuous with constant 1, as
|sin x - sin y| ≤ |x - y| for all real x, y.
Example 3.4.9. The cosine function ℝ → ℝ is Lipschitz continuous with constant 1, since
|cos x - cos y| ≤ |x - y| for all real x, y.
Example 3.4.10. The square root function f(x) = √x is Lipschitz continuous on
[1, ∞) with constant 1/2, as |√x - √y| ≤ (1/2) |x - y| for x, y ≥ 1.
Example 3.4.10. The square root function g(x) = √x on [0, ∞) is not Lipschitz
continuous; no global constant K can satisfy |√x - √y| ≤ K |x - y| on the whole domain.
Example 3.4.10. Although not Lipschitz on [0, ∞), the square root function is uniformly
continuous on that domain.