Theorem 3.3.2 (Minimum-maximum theorem / Extreme value theorem). A continuous function
f : [a, b] → ℝ attains an absolute minimum and an absolute maximum on [a, b].
Example 3.3.3. For f x = x ^ 2 + 1 on [-1, 2], the minimum is achieved at x = 0
with value f 0 = 1 and the maximum at x = 2 with value f 2 = 5. On the larger interval
[-10, 10], the maximum occurs at the endpoints x = 10 or x = -10.
Example 3.3.4. The identity function f : ℝ → ℝ, given by f x = x, achieves neither
a minimum nor a maximum on ℝ, illustrating that bounded intervals are required to guarantee
extrema.
Example 3.3.5. The function f : (0, 1) → ℝ given by f x = 1 / x is continuous on the
open interval but achieves neither a minimum nor a maximum. The values are unbounded as x
approaches 0, while as x → 1 the values tend to 1 with f x > 1 for all x ∈ (0, 1), so
no point of the domain yields the value 1. This shows the need for a closed interval in the
extreme value theorem.
Example 3.3.6. On the closed, bounded interval [0, 1], consider
f : [0, 1] → ℝ given by f x = 1 / x for x > 0 and f 0 = 0. The function is not
continuous at 0, and because the values blow up near 0, it fails to attain a maximum
on [0, 1] despite the domain being compact.
Instances For
Lemma 3.3.7 (Bolzano's intermediate value theorem). For a continuous function
f : [a, b] → ℝ with f a < 0 and 0 < f b, there exists a point c strictly between
a and b such that f c = 0.
Theorem 3.3.8 (Bolzano's intermediate value theorem). Let f : [a, b] → ℝ be
continuous. If a real number y satisfies f a < y < f b or f a > y > f b, then there is
some c strictly between a and b such that f c = y.
Example 3.3.9 (Bisection method). For f x = x ^ 3 - 2 x ^ 2 + x - 1, we have
f 1 = -1 and f 2 = 1, so by the intermediate value theorem there is a root
c ∈ (1, 2). Evaluating at midpoints shows sign changes on nested intervals:
f (3/2) < 0, f (7/4) < 0, and 0 < f (15/8), so the root lies in
(7/4, 15/8), numerically near 1.7549.
Proposition 3.3.10. A real polynomial of odd degree has a real root.
Example 3.3.12. The function
f x = sin (1 / x) for x ≠ 0 and f 0 = 0 is discontinuous at 0, yet it still
has the intermediate value property: whenever a < b and y lies strictly between
f a and f b (in either order), there exists some c ∈ (a, b) with f c = y.
Instances For
If f has a minimum at xmin and a maximum at xmax on [a, b], then the image lies
between the endpoint values.
If the minimum and maximum values are distinct, then every value between them is
achieved on [a, b].
Corollary 3.3.13. If f : [a, b] → ℝ is continuous, then the image f '' [a, b] is
either a closed and bounded interval or a single point.