Lemma 2.2.1 (Squeeze lemma): If real sequences a, x, b satisfy
a n ≤ x n ≤ b n for every n, and both a and b converge to the same
limit l, then x also converges to l, so
lim_{n → ∞} x_n = lim_{n → ∞} a_n = lim_{n → ∞} b_n.
A sequence squeezed between two convergent sequences with common limit is itself convergent with that limit.
Example 2.2.2: By bounding 1 / (n √n) (starting at n = 1) between the
constant 0 sequence and 1 / n, and using the squeeze lemma together with
lim_{n → ∞} 1 / n = 0, we conclude lim_{n → ∞} 1 / (n √n) = 0.
Lemma 2.2.3: If convergent real sequences x and y satisfy
x n ≤ y n for every n, then their limits obey
lim_{n → ∞} x_n ≤ lim_{n → ∞} y_n.
A convergent sequence with pointwise nonnegative terms has a nonnegative limit.
A pointwise lower bound for a convergent sequence bounds its limit below.
A pointwise upper bound for a convergent sequence bounds its limit above.
Corollary 2.2.4: (i) If a convergent real sequence has nonnegative terms,
then its limit is nonnegative. (ii) If a convergent real sequence is bounded
between real numbers a and b, then its limit also lies between a and
b.
Proposition 2.2.5: For convergent real sequences x and y, the usual
algebraic operations preserve convergence. (i) The sum sequence converges to
the sum of the limits. (ii) The difference sequence converges to the
difference of the limits. (iii) The termwise product converges to the product
of the limits. (iv) If lim_{n → ∞} y_n ≠ 0 and every y n ≠ 0, then the
quotient sequence converges to the quotient of the limits.
The limit of the difference of two convergent real sequences is the difference of their limits.
The limit of the termwise product of two convergent real sequences is the product of their limits.
If a convergent real sequence y has nonzero limit and no zero terms,
then the termwise quotient of convergent sequences x and y converges to
the quotient of their limits.
Proposition 2.2.6: If a convergent real sequence satisfies x n ≥ 0 for
every n, then its termwise square roots converge to the square root of its
limit, i.e. lim_{n → ∞} √(x_n) = √(lim_{n → ∞} x_n).
Proposition 2.2.7: If a real sequence x converges, then its termwise
absolute values also converge, and the limit is the absolute value of the
original limit, so lim_{n → ∞} |x_n| = |lim_{n → ∞} x_n|.
The absolute value of a convergent real sequence is also convergent.
Example 2.2.8: Starting from x₁ = 2 and defining
x_{n+1} = x_n - (x_n^2 - 2) / (2 x_n), the recursion is well-defined because
each term stays positive. The sequence is monotone decreasing and bounded
below, so it converges; taking limits in the recurrence gives x = √2, so
the limit equals √2.
Equations
Instances For
Every term of the Newton sequence for √2 is positive, so the recurrence
is well-defined.
For every n, (x_n)^2 - 2 is nonnegative along the Newton sequence.
The Newton sequence for √2 is monotone decreasing.
The Newton sequence for √2 converges to √2.
The Newton sequence for √2 stays positive, decreases monotonically, and
converges to √2.
Example 2.2.9: For the recursion x_{n+1} = x_n^2 + x_n, starting at
x₁ = 1 yields an unbounded sequence and hence no limit, while starting at
x₁ = 0 gives the constant zero sequence whose limit is 0. The long-term
behavior therefore depends on the initial value.
Instances For
Lower bound for the quadratic recursion started at 1.
With initial value 1, the quadratic recursion grows without bound.
The quadratic recursion started at 1 does not converge.
The quadratic recursion started at 0 is identically zero.
Starting the quadratic recursion at 0 yields a sequence converging to
0.
Proposition 2.2.10: If x is a real sequence and there exists x₀ : ℝ
and a convergent sequence a with lim_{n → ∞} a_n = 0 such that
|x_n - x₀| ≤ a_n for every n, then x converges to x₀.
A sequence controlled by a convergent error term with vanishing limit is convergent.
Proposition 2.2.11: Let c > 0. (i) If c < 1, then lim_{n → ∞} c^n = 0.
(ii) If c > 1, then the sequence (c^n) is unbounded.
Lemma 2.2.12 (Ratio test for sequences): For a real sequence x with
no zero terms, suppose the limit L = lim_{n → ∞} |x_{n+1}| / |x_n| exists.
(i) If L < 1, then x converges to 0. (ii) If L > 1, then x is
unbounded and therefore diverges.
Example 2.2.14: Using the ratio test on the sequence (n / (1 + ε)^n),
for any ε > 0 we get n / (1 + ε)^n → 0, which forces
1 ≤ n^(1/n) < 1 + ε for large n. Hence lim_{n → ∞} n^(1/n) = 1.