Monotonicity of t ↦ -sqrt (1 - t) on (-∞, 1).
Remark 7.0.25: Theorem 7.5 can be used to show convexity. For example, the function
f(x) = -(1 - |x|^2)^{1/2} on ℝ^n (with f(x) = +∞ for |x| ≥ 1) is convex by
verifying the limit relation in Theorem 7.5 at boundary points.
If iInf f < α, then some point in ri (dom f) satisfies f x < α.
Horizontal section of the embedded epigraph corresponds to the ≤-sublevel set.
A point in ri (dom f) with f x < α yields a point of ri (epi f) at height α.
The horizontal hyperplane at height α meets ri (epi f) when α > inf f.
Points of the form appendAffineEquiv n 1 (y, zα) lie in the horizontal plane M.
The horizontal slice of the embedded epigraph is the image of the ≤-sublevel set.
The horizontal slice map is a homeomorphism onto the plane M.
Pull back closure and relative interior across the horizontal slice homeomorphism.
The strict inequality set is relatively open in affineSpan domf.
A nonempty relatively open subset of an affine subspace has full affine span.
The closure of the embedded epigraph equals the embedded epigraph of the closure.
Theorem 7.6 auxiliary proof #
Auxiliary proof for Theorem 7.6.
Theorem 7.6: Let f be a proper convex function, and let α ∈ ℝ with
α > inf f. The convex level sets {x | f x ≤ α} and {x | f x < α} have the same
closure and the same relative interior, namely {x | (cl f) x ≤ α} and
{x ∈ ri (dom f) | f x < α}. Furthermore, they have the same dimension as dom f.
The right-hand side of the strict-sublevel closure formula is nonempty for the zero function.
Text 7.0.17: The closure and relative interior formulas in Theorem 7.6 can fail when
α = inf f.
Text 7.0.18: If α < inf f then {x | f x ≤ α} is empty and the formulas are
trivial. The case α = inf f is more subtle and can also lead to failure of the
formulas; see the example above.
Relative openness means the relative interior agrees with the set.
Corollary 7.6.1: If f is a closed proper convex function whose effective domain is
relatively open (in particular if effectiveDomain Set.univ f is an affine set), then for
inf f < α < +∞ one has ri {x | f x ≤ α} = {x | f x < α} and
cl {x | f x < α} = {x | f x ≤ α}.